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Question: Answered & Verified by Expert
At time t second, a particle of mass 3 kg has position vector r metre where r=(3t) i^-(4 cos t)j^ . The impulse of the force during the time interval 0 t π2   is
PhysicsLaws of MotionNEET
Options:
  • A 12j^   N-s
  • B 9j^  N-s
  • C 4j^  N-s
  • D 14j^  N-s
Solution:
2860 Upvotes Verified Answer
The correct answer is: 12j^   N-s
r = 3t i^-4cost j^

v=d rdt=3i^+4sint j^

a=d2 rdt2=4cost j^

F=ma=12cost j^

Impluse = 0π2F dt=12 0π2cost dt

=12 sint0π2=12 N-s

The direction of impulse will be in the direction of force.

Impulse =12 N-sj^

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