At very high pressures, the compressibility factor of one mole of a gas is given by:

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At very high pressures, the compressibility factor of one mole of a gas is given by:

ChemistryStates of MatterJEE MainJEE Main 2016 (09 Apr Online)

Options:

A $1 + \frac{P b}{R T}$
B $\frac{P b}{R T}$
C $1 - \frac{P b}{R T}$
D $1 - \frac{b}{(V R T)}$

Solution:

1299 Upvotes Verified Answer

The correct answer is:

1 + \frac{P b}{R T}

(P + \frac{a}{V^{2}}) (V - b) = R T

at very high pressure

P ≫ \frac{a}{V^{2}}

P (V - b) = R T

P V - P b = R T

∴ Z = 1 + \frac{P b}{R T}

compressibility factor

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