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Question: Answered & Verified by Expert
At which of the $\mathrm{f}$ (a) For one gm mole; average kinetic energy $=\frac{3}{2} R T$. the molecules of a gas have twice the average kinetic energy they have at $20^{\circ} \mathrm{C}$
PhysicsKinetic Theory of GasesJEE Main
Options:
  • A $40^{\circ} \mathrm{C}$
  • B $80^{\circ} \mathrm{C}$
  • C $313^{\circ} \mathrm{C}$
  • D $586^{\circ} \mathrm{C}$
Solution:
2547 Upvotes Verified Answer
The correct answer is: $313^{\circ} \mathrm{C}$
Average kinetic energy $\propto$ Temperature
$\begin{aligned}& \frac{E_1}{E_2}=\frac{T_1}{T_2} \Rightarrow \frac{E}{2 E}=\frac{T_1}{T_2} \Rightarrow T_2=2 T_1 \\\Rightarrow & T_2=2(273+20)=586 \mathrm{~K}=313^{\circ} \mathrm{C}\end{aligned}$

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