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Average distance of the earth from the sun is $L_1$. If one year of the earth $=D$ days, one year of another planet whose average distance from the sun is $L_2$ will be
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$D\left(\frac{L_2}{L_1}\right)^{3 / 2}$ days
According to Kepler's third law, $T^2 \propto r^3$ or $T \propto r^{3 / 2}$
$\therefore \quad \frac{D^{\prime}}{D}=\left(\frac{L_2}{L_1}\right)^{3 / 2} \quad$ or $D^{\prime}=D\left(\frac{L_2}{L_1}\right)^{3 / 2}$ days
$\therefore \quad \frac{D^{\prime}}{D}=\left(\frac{L_2}{L_1}\right)^{3 / 2} \quad$ or $D^{\prime}=D\left(\frac{L_2}{L_1}\right)^{3 / 2}$ days
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