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$\mathrm{B}(\mathrm{OH})_3+\mathrm{NaOH} \rightleftharpoons \mathrm{NaBO}_2+\mathrm{Na}\left[\mathrm{B}(\mathrm{OH})_4\right]+\mathrm{H}_2 \mathrm{O}$.
How can this reaction is made to proceed in forward direction?
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How can this reaction is made to proceed in forward direction?
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The correct answer is:
Addition of cis 1, 2 diol
Addition of cis 1, 2 diol
This reaction is reversible reaction because sodium metaborate, $\mathrm{Na}^{+}\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$formed by the reaction between $\mathrm{B}(\mathrm{OH})_3$ and $\mathrm{NaOH}$ gets hydrolysed to regenerate $\mathrm{B}(\mathrm{OH})_3$ and $\mathrm{NaOH}$
If, some quantity of polyhydroxy compound like cis-1, 3-diol, catechol, glycerol etc. is added to the reaction mixture. The $\mathrm{B}(\mathrm{OH})_3$ combines with such polyhydroxy compound to give chelated complex compound. Due to complex compound formation, stability increases and due to higher stability of complex, reaction moves in forward direction.
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