Balance the following redox reactions by ion - electron method. $ \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq})+\mathrm{SO}_{2}(\mathrm{~g}) \longrightarrow \mathrm{Cr}^{3+}(\mathrm{aq})+\mathrm{SO}_{4}^{2-}(\mathrm{aq}) \quad $ (in acidic solution) by selecting any of the choices correctly

Question

Balance the following redox reactions by ion - electron method. $ \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq})+\mathrm{SO}_{2}(\mathrm{~g}) \longrightarrow \mathrm{Cr}^{3+}(\mathrm{aq})+\mathrm{SO}_{4}^{2-}(\mathrm{aq}) \quad $ (in acidic solution) by selecting any of the choices correctly, One moles of $ \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} $ oxidises $ 3 $ moles of $ \mathrm{SO}_{2} $, One mole of $ \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} $ produces $ 3 $ moles of $ \mathrm{SO}_{4}^{2-} $, One moles of $ \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} $ oxidises $ 3 $ moles of $ \mathrm{SO}_{2} $ e mole of $ \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} $ produces $ 3 $ moles of $ \mathrm{SO}_{4}^{2-} $, One mole of $ \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} $ ion oxidises $ 2 $ moles of $ \mathrm{SO}_{2} $

MARKS App · Accepted Answer

Cr 2 O 7 2 - + 1 4 H aq + + 6 e - ⟶ 2 Cr aq 3 + + 7 H 2 O RHR SO 2 + 2 H 2 O ⟶ SO 4 2 - + 4 H + + 2 e - OHR } × 3 ------------------------------------------------------------------- Cr 2 O 7 aq 2 - + 2 H aq + + 3 SO 2 ⟶ 2 Cr aq 3 + + 3 SO 4 aq 2 - + H 2 O e

Search any question & find its solution

Looking for more such questions to practice?