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Be2C + 4 H2O 2 X + CH4
X + 2 HCl Y
'X' and 'Y' formed in the above two reactions are -
Options:
X + 2 HCl Y
'X' and 'Y' formed in the above two reactions are -
Solution:
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Verified Answer
The correct answer is:
Be(OH)2 and BeCl2 ; respectively
Be2C + 4H2O → 2 Be(OH)2 + CH4
Thus, 'X' is Be(OH)2.
Next, X reacts with HCl to form:
Be(OH)2 + 2HCl → BeCl2 + 2H2O
Thus, 'Y' is BeCl2.
Thus, 'X' is Be(OH)2.
Next, X reacts with HCl to form:
Be(OH)2 + 2HCl → BeCl2 + 2H2O
Thus, 'Y' is BeCl2.
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