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Question: Answered & Verified by Expert
Because of lanthanoid contraction, which of the following pairs of elements have nearly the same atomic radii? (Number in the parenthesis are atomic numbers).
Chemistryd and f Block ElementsNEETNEET 2015 (Phase 1)
Options:
  • A Ti 22 and Zr 40
  • B Zr 40 and Nb 41
  • C Zr 40 and Hf 72
  • D Zr 40 and Ta 73
Solution:
2898 Upvotes Verified Answer
The correct answer is: Zr 40 and Hf 72

Zr 40 and Hf 72: Because of the lanthanoid contraction, Zr (atomic radii 160 pm) and Hf (atomic radii 158 pm) have nearly the same atomic radii.

Lanthanoids include the elements from lanthanum La Z=57 to lutetium Lu Z=71. Zirconium Zr 40 belong to the second transition series 4d and Hf 72 belongs to the third transition series 5d. Lanthanoid contraction is related to the intervention of the 4f-orbitals, which are filled before the 5d-series of elements start. The filling of 4f, if orbitals before 5d-orbitals result in a regular decrease in atomic radii, which compensates the expected increases in atomic size with increasing atomic number. As a result of lanthanoid contraction, the elements of second and third transition series have almost similar atomic radii.

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