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$\mathrm{BeF}_2,$ is soluble in water whereas fluorides of other alkaline earth metals are insoluble because of
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greater hydration energy of $\mathrm{Be}^{2+}$ ion as compared to its lattice energy.
$\mathrm{Be}^{2+}$ being small in size is heavily hydrated and heat of hydration exceeds the lattice energy. Hence $\mathrm{BeF}_{2}$ is soluble in water.
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