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\begin{array}{|c|c|c|c|c|}
\hline \mathrm{X} & 1 & 2 & 3 & 4 \\
\hline Frequency & 2 & 3 & f & 5 \\
\hline
\end{array} The frequency distribution of a discrete variable $X$ with one missing frequency $f$ is given above. If the arithmetic mean of
$X$ is $\frac{23}{8}$, what is the value of the missing frequency?
Options:
\hline \mathrm{X} & 1 & 2 & 3 & 4 \\
\hline Frequency & 2 & 3 & f & 5 \\
\hline
\end{array} The frequency distribution of a discrete variable $X$ with one missing frequency $f$ is given above. If the arithmetic mean of
$X$ is $\frac{23}{8}$, what is the value of the missing frequency?
Solution:
1576 Upvotes
Verified Answer
The correct answer is:
6
Arithmetic mean $=\frac{2 \times 1+3 \times 2+3 f+4 \times 5}{2+3+f+5}$
$\Rightarrow \frac{23}{8}=\frac{28+3 f}{10+f}$
$230+23 f=224+24 f$
$\Rightarrow f=6$
$\Rightarrow \frac{23}{8}=\frac{28+3 f}{10+f}$
$230+23 f=224+24 f$
$\Rightarrow f=6$
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