Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
\( \begin{array}{l} \mathrm{CaSO}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O} \stackrel{\Delta, 120^{\circ} \mathrm{C}}{\longrightarrow} \mathrm{A} \\ \mathrm{CaSO}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O} \stackrel{\Delta, 200^{\circ} \mathrm{C}}{\longrightarrow} \mathrm{B} \end{array} \) In the above reaction, \( \mathrm{A} \) and \( \mathrm{B} \), respectively, are:
Chemistrys Block ElementsJEE Main
Options:
  • A \( \mathrm{CaSO}_{4}, \mathrm{CaSO}_{4} \cdot \frac{1}{2} \mathrm{H}_{2} \mathrm{O} \)
  • B \( \mathrm{CaSO}_{4} \cdot \frac{1}{2} \mathrm{H}_{2} \mathrm{O}, \mathrm{CaSO}_{4} \)
  • C \( \mathrm{CaSO}_{4} \cdot \frac{1}{2} \mathrm{H}_{2} \mathrm{O} \), Gypsum.
  • D Gypsum, \( \mathrm{CaSO}_{4} \).
Solution:
2125 Upvotes Verified Answer
The correct answer is: \( \mathrm{CaSO}_{4} \cdot \frac{1}{2} \mathrm{H}_{2} \mathrm{O}, \mathrm{CaSO}_{4} \)

CaSO4·2H2O at120oC CaSO4·12H2O+112H2O

The commercial name of the compound Calcium sulphate hemihydrate, i.e., Plaster of Paris.

CaSO4·2H2O , 200°C anhydrous CaSO4+2H2O

Anhydrous calcium sulphate formed this way is commonly called dead burnt plaster.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.