In the above question, all the forces are acted in the lower block and there is no force acting on the upper block, now the value friction force will be, 

$f_l=\left(m_1+m_2\right)g{\mu }_l$, here ${\mu }_l=0.55, m_1=3 \mathrm{kg}$ and $m_2=7 \mathrm{kg}$, now the friction force between lower block and surface, 
$f_l=\left(3+7\right)10\times 0.55=55 \mathrm{N}$,

Which is greater than, applied force so no blocks will move and no force will act in the upper block so the net friction force between the lower block and the upper block will be zero.