Body A of mass 4 m moving with speed u collides with another body B of mass 2 m at rest. The collision is head on and elastic in nature. After the collision, the fraction of energy lost by the colliding body A is

Question

Body A of mass 4 m moving with speed u collides with another body B of mass 2 m at rest. The collision is head on and elastic in nature. After the collision, the fraction of energy lost by the colliding body A is, 1 9, 8 9, 4 9, 5 9

MARKS App · Accepted Answer

4 m u + 0 = 4 m v 1 + 2 m v 2 ⇒ 2 u = 2 v 1 + v 2 … ( A ) For elastic collision, e = 1 ⇒ u = v 2 - v 1 … ( B ) From A and B , 4 u = 3 v 2 ⇒ v 2 = 4 3 u and v 1 = u 3 Fraction of energy lost by ( A ) , = 1 2 4 m u 2 - 1 2 4 m v 1 2 1 2 4 m u 2 = u 2 - u 2 9 u 2 = 8 9

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