Bond enthalpies of $ \mathrm{A}_{2}, \mathrm{~B}_{2} $ and $ \mathrm{AB} $ are in the ratio $ 2: 1: 2 $. If bond enthalpy of formation of $ \mathrm{AB} $ is $ -100 \mathrm{KJ} \mathrm{mol}^{-1} $. The bond enthalpy of $ \mathrm{B}_{2} $ is

Question

Bond enthalpies of $ \mathrm{A}_{2}, \mathrm{~B}_{2} $ and $ \mathrm{AB} $ are in the ratio $ 2: 1: 2 $. If bond enthalpy of formation of $ \mathrm{AB} $ is $ -100 \mathrm{KJ} \mathrm{mol}^{-1} $. The bond enthalpy of $ \mathrm{B}_{2} $ is, $ 100 \mathrm{KJmol}^{-1} $, $ 50 \mathrm{KJmol}^{-1} $, $ 200 \mathrm{KJmol}^{-1} $, $ 150 \mathrm{KJmol}^{-1} $

MARKS App · Accepted Answer

Assume bond strength of A 2 = 2 X , then, B 2 = X , AB = 2 X Δ r H Θ = ∑ Δ diss H Θ - ( R ) ∑ Δ diss H Θ ( P ) 1 2 A 2 + 1 2 B 2 → AB X + X 2 - 2 X = - 100 kJ mol - 1 X = 200 kJ mol - 1

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