Boolean relation at the output stage- Y for the following circuit is:

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Boolean relation at the output stage-

Y

for the following circuit is:

PhysicsSemiconductorsJEE MainJEE Main 2020 (08 Jan Shift 1)

Options:

A $\bar{A} + \bar{B}$
B $A + B$
C $A ∙ B$
D $\bar{A} ∙ \bar{B}$

Solution:

1054 Upvotes Verified Answer

The correct answer is:

\bar{A} ∙ \bar{B}

First part of figure shown is OR gate and
Second part of figure shown is NOT gate
So

Y_{P} = O R + N O T = N O R g a t e

Y = \bar{A + B} = \bar{A} . \bar{B}

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