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Question: Answered & Verified by Expert
Both the strings, shown in the figure are made of the same material and have the same cross-section. The pulleys are light. The wave speed of a transverse wave in the string AB is v1 and in the CD it is v2. Then v1v2 is

PhysicsWaves and SoundNEET
Options:
  • A 1
  • B 2
  • C 2
  • D 12
Solution:
2074 Upvotes Verified Answer
The correct answer is: 12
We know that v=Tμ

Therefore v1v2=T1T2

v1v2=T2T

v1v2=12

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