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Question: Answered & Verified by Expert
Bulb B1100 W250 V and bulb B2100 W  200 V are connected across 250 V. What is potential drop across B2?

PhysicsCurrent ElectricityNEET
Options:
  • A 200 V
  • B 250 V
  • C 98 V
  • D 48 V
Solution:
2916 Upvotes Verified Answer
The correct answer is: 98 V
Resistance of bulb B1, R1=2502100= 625 Ω

Resistance of bulb B2, R2=2002100= 400 Ω



VR2= R2R1+R2× 250=400625+400× 250=98 V

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