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Question: Answered & Verified by Expert
By using only two resistance coils singly, in series or in parallel one should be able to obtain resistances of 3, 412 and 16 Ω. The separate resistances of the coil are
PhysicsCurrent ElectricityNEET
Options:
  • A 3 and 4
  • B 4 and 12
  • C 12 and 16
  • D 16 and 3
Solution:
1608 Upvotes Verified Answer
The correct answer is: 4 and 12
If we take R1=4 ΩR2=12 Ω then in series resistance

R = R 1 + R 2

= 4 + 1 2

=16 Ω

In parallel, resistanceR=4×124+12=3 Ω

SoR1=4 ΩR2=12 Ω

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