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By which one of the following compounds both $\mathrm{CH}_4$ and $\mathrm{CH}_3-\mathrm{CH}_3$ can be prepared in one step ?
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The correct answer is:
$\mathrm{CH}_3 \mathrm{I}$
$\mathrm{CH}_3 \mathrm{I}+2 \mathrm{H} \xrightarrow[\text { or } \mathrm{Zn}-\mathrm{Cu} / \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}]{\mathrm{Zn}+\mathrm{HCl}} \underset{\text { Methane }}{\mathrm{CH}_4}+\mathrm{HI}$


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