C 2 H 4 can react with H 2 in presence of a catalyst to form C 2 H 6 as per the following reaction, C 2 H 4 g + H 2 g ⟶ Catalyst C 2 H 6 g The amount of C 2 H 4 in grams required to produce 50 grams of C 2 H 6 is

Question

C 2 H 4 can react with H 2 in presence of a catalyst to form C 2 H 6 as per the following reaction, C 2 H 4 g + H 2 g ⟶ Catalyst C 2 H 6 g The amount of C 2 H 4 in grams required to produce 50 grams of C 2 H 6 is, 36 . 44 g, 22 . 18 g, 46 . 67 g, 57 . 11 g

MARKS App · Accepted Answer

Given reaction C 2 H 4 g + H 2 g ⟶ Catalyst C 2 H 6 g C 2 H 4 m o l e c u l a r w e i g h t = 28 , C 2 H 6 m o l e c u l a r w e i g h t = 30 , ⇒ For the form 30 gm C 2 H 6 required C 2 H 4 = 28 ⇒ For 50 the form 50 gm C 2 H 6 required C 2 H 4 = 28 × 50 30 = 46 . 67 g

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