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$\mathrm{C}_6 \mathrm{H}_6 \xrightarrow[\mathrm{H}_2 \mathrm{SO}_4]{\mathrm{HNO}_3} X \xrightarrow[\mathrm{FeCl}_3]{\mathrm{Cl}} Y$
. In the above sequence $Y$ is
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. In the above sequence $Y$ is
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The correct answer is:
3-nitrochlorobenzene
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