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Question: Answered & Verified by Expert
cosx-sinx8-sin2xdx=1plog3+sinx+cosx3-sinx-cosx+c , then p =……
MathematicsIndefinite IntegrationMHT CETMHT CET 2019 (Shift 2)
Options:
  • A 6
  • B 1
  • C 3
  • D 12
Solution:
2098 Upvotes Verified Answer
The correct answer is: 6
cosx-sinx8-sinx=1plog3+sinx+cosx3-sinx-cosx+C
Now, =cosx-sinx9-1+2sinxcosxdx
=cosx-sinx9-sin2x+cos2x+2sinxcosxdx
=cosx-sinx32-cosx+sinx2dx
Put cosx+sinx=t
-sinx+cosxdx=dt
=dt32-t2=123log3+t3-t+C
=16log3+sinx+cosx3-sinx-cosx+C
p=6

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