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$C s B r$ crystal has bcc structure. It has an edge length of 4.3 Å. The shortest interionic distance between $\mathrm{Cs}^{+}$and $\mathrm{Br}^{-}$ions is
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$3.72 Å$
Closest approach in bcc lattice
$=\frac{1}{2}$ of body diagonal $=\frac{1}{2} \times \sqrt{3} a=\frac{\sqrt{3}}{2} \times 4.3=3.72 Å$
$=\frac{1}{2}$ of body diagonal $=\frac{1}{2} \times \sqrt{3} a=\frac{\sqrt{3}}{2} \times 4.3=3.72 Å$
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