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$\mathrm{CaC}_2+2 \mathrm{D}_2 \mathrm{O} \longrightarrow$ "P" $+\mathrm{Ca}(\mathrm{OD})_2$
In the above reaction product " $\mathrm{P}$ " is
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In the above reaction product " $\mathrm{P}$ " is
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The correct answer is:
$\mathrm{C}_2 \mathrm{D}_2$
$\mathrm{CaC}_2+2 \mathrm{D}_2 \mathrm{O} \rightarrow \mathrm{Ca}(\mathrm{OD})_2+\mathrm{C}_2 \mathrm{D}_2$
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