Search any question & find its solution
Question:
Answered & Verified by Expert
Calculate change in internal energy if \(\Delta H=-92.2 \mathrm{~kJ}, P=40 \mathrm{~atm}\) and \(\Delta V=-1 \mathrm{~L}\).
Options:
Solution:
1731 Upvotes
Verified Answer
The correct answer is:
\(-88 \mathrm{~kJ}\)
\(\Delta H=\Delta E+P \Delta V\)
\(\begin{aligned}
\Delta E & =\Delta H-P \Delta V=-92.2-40 \times(-1) \times 101 \times 10^{-3} \\
& =-92.2+4.04=-88.16 \mathrm{~kJ} \approx-88 \mathrm{~kJ} .
\end{aligned}\)
\(\begin{aligned}
\Delta E & =\Delta H-P \Delta V=-92.2-40 \times(-1) \times 101 \times 10^{-3} \\
& =-92.2+4.04=-88.16 \mathrm{~kJ} \approx-88 \mathrm{~kJ} .
\end{aligned}\)
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.