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Calculate $\Lambda_{\text {HOAC }}^{\infty}$ using appropriate molar conductances of the electrolytes listed above at infinite dilution in $\mathrm{H}_2 \mathrm{O}$ at $25^{\circ} \mathrm{C}$
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$390.7$
$\Lambda_{\mathrm{HOAC}}^{\infty}=\Lambda_{\mathrm{NeOAC}}^{\infty}+\Lambda_{\mathrm{HCl}}^{\infty}-\Lambda_{\mathrm{NaCl}}^{\infty}=91.0+426.2-126.5=390.7$
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