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Calculate radius of third orbit of $\mathrm{He}^{+}$.
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Verified Answer
The correct answer is:
$238.1 \mathrm{pm}$
$$
\mathrm{r}_{\mathrm{n}}=\frac{52.9(\mathrm{n})^2}{\mathrm{Z}} \mathrm{pm}
$$
$\mathrm{He}^{+}$is a hydrogen-like species having $\mathrm{Z}=2$. Radius of the third orbit of $\mathrm{He}^{+}$
$=\mathrm{r}_3=\frac{52.9 \times(3)^2}{2} \mathrm{pm}=238.1 \mathrm{pm}$
\mathrm{r}_{\mathrm{n}}=\frac{52.9(\mathrm{n})^2}{\mathrm{Z}} \mathrm{pm}
$$
$\mathrm{He}^{+}$is a hydrogen-like species having $\mathrm{Z}=2$. Radius of the third orbit of $\mathrm{He}^{+}$
$=\mathrm{r}_3=\frac{52.9 \times(3)^2}{2} \mathrm{pm}=238.1 \mathrm{pm}$
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