Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert

Calculate the amount of electricity required to deposit 0.9 g of aluminium by electrolysis of a salt containing its ion, if the electrode reaction is

Al 3 + + 3 e - Al ;    ( atomic mass of Al  =  2 7 ,  1 F = 96500 C  )

ChemistryElectrochemistryNEET
Options:
  • A 9.65 × 10 3 C
  • B 1.93 × 10 4 C
  • C 9.65 × 10 4 C
  • D 4.34 × 10 5 C
Solution:
2550 Upvotes Verified Answer
The correct answer is: 9.65 × 10 3 C
Al 3 + + 3 e - Al ​

1 mole Al requires 3 mole e- (3 F charge) to dischage on electrode.

Also, 1 F = 96500 C.

Thus, 27 g of Al require = 3 × 9 6 5 0 0  C

0.9 g of Al requires = 3 × 9 6 5 0 0  C 2 7 × 0.9 = 9650 C .

=9.65× 10 3  C

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.