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Calculate the amount of heat (in calories) required to convert $5 \mathrm{gm}$ of ice at $0^{\circ} \mathrm{C}$ to steam at $100^{\circ} \mathrm{C}$
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Verified Answer
The correct answer is:
$3600$
Ice $\left(0^{\circ} \mathrm{C}\right)$ converts into steam $\left(100^{\circ} \mathrm{C}\right)$ in following three steps.
Total heat required $Q=Q_1+Q_2+Q_3$
$=5 \times 80+5 \times 1 \times(100-0)+5 \times 540=3600 \mathrm{cal}$
Total heat required $Q=Q_1+Q_2+Q_3$
$=5 \times 80+5 \times 1 \times(100-0)+5 \times 540=3600 \mathrm{cal}$
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