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Calculate the change in enthalpy in a chemical reaction when work done is $-800 \mathrm{~J}$ and increase in internal energy is $600 \mathrm{~J}$.
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The correct answer is:
-200 J
$\begin{aligned} & \triangle H=\Delta U+P d V \\ & =600-800 \\ & =-200 \mathrm{~J}\end{aligned}$
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