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Calculate the density of metal having volume of unit cell $64 \times 10^{-24} \mathrm{~cm}^3$ and molar mass of metal $192 \mathrm{~g} \mathrm{~mol}^{-1}$ containing 4 particles in unit cell.
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The correct answer is:
$19.93 \mathrm{~g} \mathrm{~cm}^{-3}$
$\begin{aligned} & \mathrm{d}=\frac{4 \times 192}{64 \times 10^{-24} \times 602 \times 10^{23}} \\ & =19.93 \mathrm{~g} \mathrm{~cm}^{-3}\end{aligned}$
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