Search any question & find its solution
Question:
Answered & Verified by Expert
Calculate the dispersive power for crown glass from the given data
$\begin{array}{rll} & \mu_{\mathrm{V}}=1.523 \\ \text { and } & \mu_{\mathrm{R}}=1.5145\end{array}$
Options:
$\begin{array}{rll} & \mu_{\mathrm{V}}=1.523 \\ \text { and } & \mu_{\mathrm{R}}=1.5145\end{array}$
Solution:
1710 Upvotes
Verified Answer
The correct answer is:
$0.01639$
Here, $\mu_V=1.523$ and $\mu_R=1.5145$
Mean refractive index,
$\mu=\frac{1.523+1.5145}{2}=1.51875$
Dispersive power is given by,
$\begin{aligned} \omega & =\frac{\left(\mu_V-\mu_R\right)}{(\mu-1)} \\ & =\frac{1.523-1.5145}{(1.51875-1)}=0.01639\end{aligned}$
Mean refractive index,
$\mu=\frac{1.523+1.5145}{2}=1.51875$
Dispersive power is given by,
$\begin{aligned} \omega & =\frac{\left(\mu_V-\mu_R\right)}{(\mu-1)} \\ & =\frac{1.523-1.5145}{(1.51875-1)}=0.01639\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.