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Calculate the emf of the cell in which the following reaction takes place Ni(s) + 2Ag⁺ (0.002 M) → Ni²⁺ (0.160 M) + 2Ag(s) Given that E(cell) = 1.05 V
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The correct answer is:
0.85 V
Correct Option is : (B)
0.85 V
0.85 V
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