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Calculate the energy and frequency of the radiation emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom.
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The correct answer is:
Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz
Correct Option is : (D)
Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz
Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz
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