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Question: Answered & Verified by Expert
Calculate the energy and frequency of the radiation emitted when an electron jumps from n = 3 to n = 2 in a hydrogen atom.
ChemistryStructure of AtomNEET
Options:
  • A Energy = 1.51 × 10-19Joules, Frequency = 2.56 × 1015Hz
  • B Energy = 1.51 × 10-19Joules, Frequency = 4.86 × 1015Hz
  • C Energy = 4.86 × 10-19Joules, Frequency = 1.51 × 1015Hz
  • D Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz
Solution:
2824 Upvotes Verified Answer
The correct answer is: Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz
Correct Option is : (D)
Energy = 3.02 × 10-19Joules, Frequency = 0.45 × 1015Hz

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