Calculate the enthalpy change of the following reaction H 2 C = C H 2 ( g ) + H 2 ( g ) → H 3 C - C H 3 ( g ) The bond energy of C - H , C - C , C = C , H - H are 414, 347, 615 and 453 KJ m o l - 1 respectively.

Question

Calculate the enthalpy change of the following reaction H 2 C = C H 2 ( g ) + H 2 ( g ) → H 3 C - C H 3 ( g ) The bond energy of C - H , C - C , C = C , H - H are 414, 347, 615 and 453 KJ m o l - 1 respectively., +125 kJ, -12.5 kJ, -125 kJ, +12.5 kJ

MARKS App · Accepted Answer

Δ H = Σ bond energy of reactant - Σ bond energy of product to write bond energy use proper symbols E C = C or Δ C = C H = [ 1 ( C = C ) + 4 ( C - H ) + 1 ( H - H ) ] - [ 1 ( C - C ) + 6 ( C - H ) ] = -1 ( C - C ) - 2 ( C - H ) + 1 ( C = C ) + 1 ( H - H ) = - 347 - 2 ( 414 ) + 1 ( 615 ) + 1 ( 435 ) = - 125 kJ.

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