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Question: Answered & Verified by Expert
Calculate the entropy change in melting 1 mole of ice at $273 \mathrm{~K}, \Delta \mathrm{H}_{\mathrm{f}}^{\mathrm{o}}=6.025 \mathrm{~kJ} /$ mole-
ChemistryThermodynamics (C)VITEEEVITEEE 2019
Options:
  • A $11.2 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$
  • B $22.1 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$
  • C $15.1 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$
  • D $5.1 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$
Solution:
1557 Upvotes Verified Answer
The correct answer is: $22.1 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$
$\Delta \mathrm{S}_{\mathrm{f}}=\frac{\Delta \mathrm{H}_{\mathrm{f}}}{\mathrm{T}}=\frac{6025 \mathrm{~J} \mathrm{~mol}^{-1}}{273 \mathrm{~K}}=22.1 \mathrm{JK}^{-1}$ $\mathrm{mol}^{-1}$

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