Calculate the mass of sodium carbonate required to prepare 500 ml of a semi- normal solution

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Calculate the mass of sodium carbonate required to prepare 500 ml of a semi- normal solution

ChemistrySome Basic Concepts of ChemistryNEET

Options:

A 13.25 g
B 26.5 g
C 53 g
D 6.125 g

Solution:

1248 Upvotes Verified Answer

The correct answer is: 13.25 g

N = \frac{w × 1000}{eq .wt . × volume in ml .}

e q . w t . = \frac{106}{2} = 53

w = \frac{0 .5 × 53 × 500}{1000} =13 .25 g

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