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Calculate the molality of a solution having freezing point depression $3.6 \mathrm{~K}$ and freezing point depression constant $4.8 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$.
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Verified Answer
The correct answer is:
$0.75 \mathrm{~mol} \mathrm{~kg}^{-1}$
We know
$\begin{aligned} & \Delta \mathrm{T}_{\mathrm{f}}=\mathrm{k}_{\mathrm{f}} \mathrm{m} \\ & 3.6=\mathrm{m} \times 4.8 \\ & \mathrm{~m}=0.75 \mathrm{~mol} / \mathrm{kg}\end{aligned}$
$\begin{aligned} & \Delta \mathrm{T}_{\mathrm{f}}=\mathrm{k}_{\mathrm{f}} \mathrm{m} \\ & 3.6=\mathrm{m} \times 4.8 \\ & \mathrm{~m}=0.75 \mathrm{~mol} / \mathrm{kg}\end{aligned}$
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