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Calculate the molar conductivity of $\mathrm{CH}_2 \mathrm{ClCOOH}$ at zero concentration if molar conductivities of $\mathrm{HCl}, \mathrm{KCl}$ and $\mathrm{CH}_2 \mathrm{ClCOOK}$ at zero concentration are $4.2,1.4$ and $1.1 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ respectively.
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The correct answer is:
$3.9 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
$\begin{aligned} \Lambda_{\mathrm{CH}_2 \mathrm{ClCOOH}}^{\circ} & =\Lambda_{\mathrm{CH}_2 \mathrm{ClCOOK}}^{\circ}+\Lambda_{\mathrm{HCl}}^{\circ}-\Lambda_{\mathrm{KCl}}^{\circ} \\ \Lambda_{\mathrm{CH}_2 \mathrm{ClCOOH}}^{\circ} & =1.1+4.2-1.4 \\ & =3.9 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\end{aligned}$
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