Calculate the molar solubility of $\mathrm{Ni}(\mathrm{OH}) 2$ in $0.10 \mathrm{M} \mathrm{NaOH}$. The ionic product of $\mathrm{Ni}(\mathrm{OH}) 2$ is $2.0 \times 10^{-15}$.

Question

Calculate the molar solubility of $\mathrm{Ni}(\mathrm{OH}) 2$ in $0.10 \mathrm{M} \mathrm{NaOH}$. The ionic product of $\mathrm{Ni}(\mathrm{OH}) 2$ is $2.0 \times 10^{-15}$., $4 \times 10^{-9}$, $1 \times 10^{-11}$, $2 \times 10^{-13}$, $8 \times 10^{-16}$

MARKS App · Accepted Answer

Correct Option is : (C) $2 \times 10^{-13}$

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