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Question: Answered & Verified by Expert
Calculate the number of weak hydrogen bonds in a DNA strand 204  long with 15% thymine bases.
BiologyMolecular Basis of InheritanceNEET
Options:
  • A 154
  • B 162
  • C 138
  • D 120
Solution:
1287 Upvotes Verified Answer
The correct answer is: 162
DNA length of one turn is 34 . It means one turn contains 10 base pairs. So 34 =10 base pairs.

Hence, 204 =204×10/34= 60 base pairs. As given 15% is thymine =15/100× 60=9 thymine.

Thymine pairs with adenine and hence adenine is also 9. So AT is total of 18. Total GC=60-18=42.

Total hydrogen bonds 2x AT+3x GC (AT shows double bond and GC shows triple bond) = 2 x 18 + 3 x 42=36+126=162.

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