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Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving \(1.0 \mathrm{~g}\) of polymer of molar mass 185,000 in \(450 \mathrm{~mL}\) of water at \(37^{\circ} \mathrm{C}\).
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Verified Answer
Applying the formula,
\(\begin{gathered}
\pi=C R T=\frac{n}{V} R T \\
\text { Number of moles of polymer }(n)=\frac{1.0 \mathrm{~g}}{185,000 \mathrm{~g} \mathrm{~mol}^{-1}} \\
\therefore \pi=\frac{1}{185,000} \times \frac{1}{0.45} \times 8.314 \times 10^3 \\
\\
=30.96 \mathrm{~Pa} \approx 31 \mathrm{~Pa}
\end{gathered}\)
\(\begin{gathered}
\pi=C R T=\frac{n}{V} R T \\
\text { Number of moles of polymer }(n)=\frac{1.0 \mathrm{~g}}{185,000 \mathrm{~g} \mathrm{~mol}^{-1}} \\
\therefore \pi=\frac{1}{185,000} \times \frac{1}{0.45} \times 8.314 \times 10^3 \\
\\
=30.96 \mathrm{~Pa} \approx 31 \mathrm{~Pa}
\end{gathered}\)
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