Calculate the overall complex dissociation equilibrium constant for the $\mathrm{Cu}\left(\mathrm{NH}_3\right)_4{ }^{2+}$ ion, given that $\beta_4$ for this complex is $2.1 \times 10^{13}$.

Question

Calculate the overall complex dissociation equilibrium constant for the $\mathrm{Cu}\left(\mathrm{NH}_3\right)_4{ }^{2+}$ ion, given that $\beta_4$ for this complex is $2.1 \times 10^{13}$.,

MARKS App · Accepted Answer

Overall stability constant $\left(\beta_4\right)=2.1 \times 10^{13}$ Thus, the overall dissociation constant is $=\frac{1}{\beta_4}=\frac{1}{2.1 \times 10^{13}}=4.7 \times 10^{-14}$.

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