Calculate the percentage of all the monochlorinated products obtained from the chlorination of 2 - methyl butane. The relative reactivity of 1 ∘ , 2 ∘ , and 3 ∘ hydrogen to chlorination is (1 : 3.8 : 5).

Question

Calculate the percentage of all the monochlorinated products obtained from the chlorination of 2 - methyl butane. The relative reactivity of 1 ∘ , 2 ∘ , and 3 ∘ hydrogen to chlorination is (1 : 3.8 : 5)., 15%, 45%, 20%, 25%, 14%, 35%, 23%, 28%, 12%, 30%, 22%, 29%, 17%, 36%, 20%, 23%

MARKS App · Accepted Answer

There are four different (A, B, C and D) monochloro products. Relative amount (A) (A) is obtained from the reaction of three equivalent 1 ∘ H atoms. 3 x 1 = 3.0 (B) (B) is obtained from the reaction of two equivalent 2 ∘ H atoms. 2 x 3.8 = 7.6 (C) (C) is obtained from the reaction of one equivalent 3 ∘ H atoms. 1 x 5 = 5.0 (D) (D) is obtained from the reaction of six equivalent 1 ∘ H atoms. 6 x 1 = 6.0 Total = 21.6 Therefore, percentages of the A, B, C and D monochloro products are as follows : A = 3 2 1 . 6 × 1 0 0 = 1 3 . 9 ≈ 1 4 % B = 7 . 6 2 1 . 6 × 1 0 0 = 3 5 . 1 8 ≈ 3 5 % C = 5 . 0 2 1 . 6 × 1 0 0 = 2 3 . 1 5 ≈ 2 3 % D = 6 . 0 2 1 . 6 × 1 0 0 = 2 7 . 8 ≈ 2 8 %

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		Relative amount
(A)	(A) is obtained from the reaction of three equivalent $1^{\circ}$ H atoms.	3 x 1 = 3.0
(B)	(B) is obtained from the reaction of two equivalent $2^{\circ}$ H atoms.	2 x 3.8 = 7.6
(C)	(C) is obtained from the reaction of one equivalent $3^{\circ}$ H atoms.	1 x 5 = 5.0
(D)	(D) is obtained from the reaction of six equivalent $1^{\circ}$ H atoms.	6 x 1 = 6.0 Total = 21.6