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Calculate the solid angle subtended by the periphery of an area of $1 \mathrm{~cm}^2$ at a point situated symmetrically at a distance of $5 \mathrm{~cm}$ from the area.
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Verified Answer
As we know that,
Solid angle $\Omega=\frac{\text { Area }}{\text { (Distance) }^2}$
As given that Area $=1 \mathrm{~cm}^2$, distance $=5 \mathrm{~cm}$.
Solid angle $\Omega=\frac{1 \mathrm{~cm}^2}{(5 \mathrm{~cm})^2}=\frac{1}{25}$
$=4 \times 10^{-2}$ steradian.
Solid angle $\Omega=\frac{\text { Area }}{\text { (Distance) }^2}$
As given that Area $=1 \mathrm{~cm}^2$, distance $=5 \mathrm{~cm}$.
Solid angle $\Omega=\frac{1 \mathrm{~cm}^2}{(5 \mathrm{~cm})^2}=\frac{1}{25}$
$=4 \times 10^{-2}$ steradian.
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