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Calculate the velocity of an electron placed in the second orbit of $\mathrm{Li}^{2+}$ ion.
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$3.27 \times 10^6 \mathrm{~m} \mathrm{~s}^{-1}$
The velocity of an electron in $n^{\text {th }}$ shell of the hydrogen like atom $=\frac{2.18 \times 10^6 \mathrm{~ms}^{-1} \times Z}{n}$ On putting $Z=3$ and $n=2$,
$v=\frac{2.18 \times 10^6 \times 3}{2}=3.27 \times 10^6 \mathrm{~m} \mathrm{~s}^{-1}$
$v=\frac{2.18 \times 10^6 \times 3}{2}=3.27 \times 10^6 \mathrm{~m} \mathrm{~s}^{-1}$
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