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Calculate the wave number of photon emitted during transition from the orbit $\mathrm{n}=2$ to $\mathrm{n}=1$ in hydrogen atom $\left(\mathrm{R}_{\mathrm{H}}=109677 \mathrm{~cm}^{-1}\right)$
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$82258 \mathrm{~cm}^{-1}$
$\begin{aligned} & \overline{\mathrm{V}}=\mathrm{R}_{\mathrm{H}}\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right) \\ & =109677\left(\frac{1}{1^2}-\frac{1}{2^2}\right) \\ & =82,257.75 \mathrm{~cm}^{-1}\end{aligned}$
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