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Question: Answered & Verified by Expert
Calculate the wavelength (in nm) of the spectral line of Lyman series for $\mathrm{n}=2$. (Rydberg constant $=1.1 \times 10^7 \mathrm{~m}^{-1}$ )
PhysicsAtomic PhysicsJEE Main
Options:
  • A $121$
  • B $221$
  • C $321$
  • D $421$
Solution:
1677 Upvotes Verified Answer
The correct answer is: $121$
For Lymen $n_1=1$ and $n_2=2$
And wavelength associated with electron jumping from any state to the first state according to Lyman series and it can be expressed as
$\frac{1}{\lambda}=R\left(\frac{1}{1}-\frac{1}{2^2}\right)$
i.e. $\lambda=\frac{1}{R \times\left(\frac{4-1}{4}\right)}=\frac{1}{1.1 \times 10^7 \times \frac{3}{4}}=1.215 \times 10^{-7}=121 \mathrm{~nm}$

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