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Calculate $\Delta \mathrm{U}$ if $2 \mathrm{~kJ}$ heat is released and $10 \mathrm{~kJ}$ of work is done on the system.
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The correct answer is:
$8 \mathrm{~kJ}$
From $\mathrm{I}^{\text {st }}$ law of thermodynamics
$\begin{aligned} & \Delta \mathrm{E}=\partial \mathrm{Q}+\partial \mathrm{W} \\ & =-2+10 \\ & =8 \mathrm{KJ}\end{aligned}$
$\begin{aligned} & \Delta \mathrm{E}=\partial \mathrm{Q}+\partial \mathrm{W} \\ & =-2+10 \\ & =8 \mathrm{KJ}\end{aligned}$
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