Calculate Vant Hoff factor for 0.2 m aqueous solution of K C l which freezes at - 0.680 o C . K f = 1.86 K k g m o l - 1

Question

Calculate Vant Hoff factor for 0.2 m aqueous solution of K C l which freezes at - 0.680 o C . K f = 1.86 K k g m o l - 1, 3.72, 1.83, 6.8, 1.86

MARKS App · Accepted Answer

m = 0.2 , Δ T f = 0 - - 0.68 = 0.6 8 0 C , k f = 1.86 K k g m o l - 1 K C l ⇒ n = 2 , i = ? Δ T f = i ^ × k f × m 0.68 = i ^ × 1.86 × 0.2 ⇒ i ^ = 1.83

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